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In lua's case, the language is intended to be an embedded scripting language, so any changes that make the language more complex or potentially make the compiler/runtime even slightly larger or slower may go against this objective Vim.lsp.config(lua_ls, { settings = { lua = { diagnostics = { globals = { vim }}}}}) i believe you have tried to do something similar in your code, and you can probably reuse everything you have in your lua table as well If you implement each and every tiny feature, you can end up with a 'kitchen sink' language
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I have seen the hash character '#' being added to the front of variables a lot in lua Asked 15 years, 9 months ago modified 4 years, 8 months ago viewed 324k times Because control structures in lua only consider nil and false to be false, and anything else to be true, this will always enter the if statement, which is not what you want either
There is no way that you can use binary operators like those provided in programming languages to compare a single variable to a list of values.
Any idea why this is wrong in lua If pieza == 1 then if rotacion == 1 then piezas = cuadrado1 else if rotacion == 2 then piezas = 45 if you are splitting a string in lua, you should try the string.gmatch () or string.sub () methods Use the string.sub () method if you know the index you wish to split the string at, or use the string.gmatch () if you will parse the string to find the location to split the string at
Example using string.gmatch () from lua 5.1 reference manual: } full userdata is a raw memory area with no predefined operations which offers from lua So userdata must be managed by the garbage collector In the other hand, light userdata is just a value that represents a c pointer (that is, a void * value)
Light userdata do not need to be managed by the garbage collector (and are.
I need something like the pseudocode below. How to check if a table contains an element in lua
